Take P1 and P2 as two different real points on a line a, and take point P different from P2. From the theory about homogeneous coordinates we know that
PP1
----- = (P1,P2,P) = the dividing ratio of point P with respect to (P1,P2)
PP2
Remark: If (P1,P2,P) < 0, point P is between P1 and P2.
In a cartesian coordinate system we take P(x,y); P1(x1,y1); P2(x2,y2). Then we know :
x1 - k x2x = ------------ and
1 - k y1 - k y2y = -------------
1 - kSolving these equations for k, we find
x - x1k = -------- and
x - x2 y - y1 k = --------- y - y2We also know that the ideal point of P1P2 has a dividing ratio = 1.
Take
four different, regular points A,B,C,D on a line.
By definition we have :
cross ratio of the ordered points A,B,C,D (A,B,C)= ---------
(A,B,D)
We denote the cross ratio of the ordered points A,B,C,D as (A,B,C,D).
Take A(x1,y1),B(x2,y2),C(x3,y3),D(x4,y4) on a line.
(A,B,C) CA DA x3 - x1 x4 - x1
(A,B,C,D) = -------- = ---- : ---- = --------- : ----------
(A,B,D) CB DB x3 - x2 x4 - x2
y3 - y1 y4 - y1
= -------- : ----------
y3 - y2 y4 - y2
If
(A,B,C,D) = -1 , we say that
A,B,C,D are in harmonic range or
A,B,C,D is a harmonic system of points or
C and D are harmonic conjugate points with respect to A and B.
D is the harmonic conjugate point to C with respect to A and B.
(A,B,C,D) = -1<=>
x3 - x1 x4 - x1
-------- : -------- = -1x3 - x2 x4 - x2
<=>
x3 - x1 x4 - x1
-------- = - -------x3 - x2 x4 - x2
<=>
(x3 - x1)(x4 - x2) = - (x4 - x1)(x3 - x2)<=>
...<=>
2(x1 x2 + x3 x4) = (x1 + x2)(x3 + x4)
Similarly, we find
(A,B,C,D) = -1<=>
2(y1 y2 + y3 y4) = (y1 + y2)(y3 + y4)
· ·
· · (A,B,C,D) = -1
· · <=>
· · (A,B,C)
· · -------- = -1
· · (A,B,D)
· · <=>
· · (A,B,C) = - (A,B,D)
· · <=>
· · (A,B,C) or (A,B,D) is < 0
· · <=>
· · C or D is between A and B (exclusive or)
· ·
· · (A,B,C,D) = -1 <=> (B,A,C,D) = -1 <=> (A,B,D,C) = -1 <=> (B,A,D,C) = -1
· ·
· · (A,B,C,D) = -1 <=> (C,D,A,B) = -1 <=> (D,C,B,A) = -1
· ·
· · then x2 = - x1 and y2 = - y1 and so
· ·
· · (A,B,C,D) = -1
· · <=>
· · 2(x1 x2 + x3 x4) = (x1 + x2)(x3 + x4)
· · <=>
· · 2(-x1 x1 + x3 x4) = 0
· · <=>
· · x12 = x3 x4
· ·
· · Similarly
· ·
· · y12 = y3 y4
· ·
· · (A,B,C,D) = -1
· · <=>
· · 2(x1 x2 + x3 x4) = (x1 + x2)(x3 + x4)
· · <=>
· · 2(x3 x4) = x2(x3 + x4)
· · <=>
· · 2 1 1
· · --- = --- + ----
· · x2 x3 x4
· · <=>
· · x2 is the harmonic mean of x3 and x4
In an arbitrary coordinate system we have A(x1,y1,z1), B(x2,y2,z2). Since C and D are on line AB, there is a h and h' such that
C(x1 + h x2, y1 + h y2, z1 + h z2) D(x1 + h' x2, y1 + h' y2, z1 + h' z2)Then:
(A,B,C) =x1 + h x2 x1
--------- - ----z1 + h z2 z1 h z2
---------------- = ... = ... = ------x1 + h x2 x2 z1
--------- - ---z1 + h z2 z2
Similarly
- h' z2 (A,B,D) = -------- z1And from these results
h (A,B,C,D) = --- h'
Say A,B,C,D are four different collinear points in the projective plane. Then
A(x1,y1,z1), B(x2,y2,z2),C(x1 + h x2, y1 + h y2, z1 + h z2), D(x1 + h' x2, y1 + h' y2, z1 + h' z2)
Now BY DEFINITION :
h (A,B,C,D) = --- h'
and
all previous properties hold.
It can be proved that cross ratio is a projective invariant.
With previous definition :
(A,B,C,D) = -1 <=> h' = - h <=> h + h' = 0
Choose A(x1,y1,1) and B(x2,y2,1) different and regular points.
C(x1 + h x2, y1 + h y2, 1 + h)
D(x1 + h' x2, y1 + h' y2, 1 + h') If h = -1 and h' = 1 then (A,B,C,D) = -1but then we have
C(x1 - x2, y1 - y2, 0) and D(x1 + x2, y1 + y2, 2)
<=>
x1 + x2 y1 + y2
C(x1 - x2, y1 - y2, 0) and D( --------,---------, 1)
2 2
<=>
C is the ideal point of AB and D is the midpoint of [AB]
Conclusion:
The midpoint of the segment [AB] is the harmonic conjugate point to the ideal
point of the line AB with respect to A and B.
Take an ordered quartet of concurrent lines (a,b,c,d) in the projective plane.
a: u1 x + v1 y + w1 z = 0 b: u2 x + v2 y + w2 z = 0 c: (u1 + h u2)x + (v1 + h v2)y + (w1 + h w2)z = 0 d: (u1 + h'u2)x + (v1 + h'v2)y + (w1 + h'w2)z = 0
A line e intersect these lines respectively in A,B,C and D.
e: uo x + vo y + wo z = 0then
A has coordinates (x1,y1,z1) =| vo wo | | uo wo | | uo vo |
( | v1 w1 | , - | u1 w1 | , | u1 v1 | )
B has coordinates (x2,y2,z2) =| vo wo | | uo wo | | uo vo |
( | v2 w2 | , - | u2 w2 | , | u2 v2 | )
C has coordinates| vo wo | | uo wo | | uo vo |
( | v1+hv2 w1+hw2|, - | u1+hu2 w1+hw2| , | u1+hu2 v1+hv2 | )
| vo wo | | vo wo | | uo wo | | uo wo |
=( | v1 w1 | + h| v2 w2 | , - | u1 w1 |- h| u2 w2 | ,
| uo vo | | uo vo |
| u1 v1 |+ h | u2 v2 | )
= (x1 + h x2, y1 + h y2, s1 + h z2)
and here the same h appears as in the line c!
Similarly we find for D (x1 + h'x2, y1 + h'y2, s1 + h'z2)
and here the same h' appears as in the line d
From this, we deduce an important corollary : If the cross ratio (a,b,c,d) = k then the cross ratio (A,B,C,D) = k, and this result is independent of the choice of the line e! So, we can define
From previous conclusion we can state: The cross ratio (a,b,c,d) is by definition the cross ratio of the intersection points of the ordered quartet of lines with an arbitrary line.
The
ordered quartet of lines is harmonic if and only if (a,b,c,d) = -1. we say that
a,b,c,d are in harmonic range or
a,b,c,d is a harmonic system of points or
c and d are harmonic conjugate points with respect to a and b.
d is the harmonic conjugate point to c with respect to a and b.
If in a quartet of lines a,b,c, and d, the line c is orthogonal to d, then
(a,b,c,d) = -1 <=> b and c are the bisectors of a and b
The proof is left as an exercise.
We start from the figure

We'll prove that (a,b,c,d) = -1 and (A,B,C,D) = -1
(A,B,C,D) = (a,b,c,d)
intersection with line A'D' = (A',B',C',D') = (S'A',S'B',S'C',S'D') = intersection with line AD = (B,A,C,D)Thus, k = (A,B,C,D) = (B,A,C,D)CA DA CB DB
Now (A,B,C,D) = --- : ---- and (B,A,C,D) = --- : ----CB DB CA DA
So, 1k = --- <=> k2 = 1 <=> k = -1 or k = 1
k
But
a cross ratio = 1 is impossible for a quartet of points.
So, (A,B,C,D) = -1 and (a,b,c,d) = -1
· ·
· · -1 = (a,b,c,d) = (A,B,C,D) = (A',B',C',D') = (S'A',S'B',S'C',S'D')
· ·
· · -1 = (D'C,D'C',D'S',D'S) = ...